Lia's Math – Home page

Pythagoras theorem, demonstration – one of many – extra

Posted in Math Theory by Lia on 06/01/2017

Pythagoras theorem, demonstration – one of many

Proof that:

For this demonstration we are going to use the same drawing as the one used in the previous page:

Pithagora theoreme-demonstration

To demonstrate that those triangles are equal is enough to show that all triangles have one side equal and the two adjacent angles with that side equal as well.

1. all four triangles have one of the side equal:

This side is the hypotenuse of the right triangle and it is a given value (the side of the smaller square).

2.    (angle rays, sides of the triangles, are perpendicular to each other)

3.    (angle rays, sides of the triangles, are perpendicular to each other)

This means that:

 

Pythagoras theorem, demonstration – one of many

 

 

 

 

 

 

 

 

 

Tagged with: ,